Which of the following compounds gives an eve | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Hoffmann's exhaustive methylation $(HEM)$ and elimination is a process used to degrade amines. The number of cycles required depends on the struct

Vedclass · Accepted Answer

Both $(a)$ and $(b)$

Vedclass · Answer

(D) Hoffmann's exhaustive methylation $(HEM)$ and elimination is a process used to degrade amines. The number of cycles required depends on the structure of the amine.$(a)$ Piperidine is a secondary cyclic amine. It undergoes $2$ cycles of $HEM$ and elimination to form $1,5$-pentadiene.$(b)$ Decahydroquinoline is a secondary cyclic amine. It also undergoes $2$ cycles of $HEM$ and elimination.Since both $(a)$ and $(b)$ undergo an even number $(2)$ of cycles,the correct option is $(d)$.

Which of the following compounds gives an even number of Hoffmann's exhaustive methylation and elimination cycles?

Similar Questions

Which one of the following compounds when heated with $KOH$ and a primary amine gives the carbylamine test?

The product$(s)$ of the following reaction sequence is(are):
Aniline $\xrightarrow[\text{ii) } KBrO_3/HBr]{\text{i) Acetic anhydride/pyridine}}$ $\xrightarrow[\text{iv) } NaNO_2/HCl, 273-278 \ K]{\text{iii) } H_3O^+, \text{heat}}$ $\xrightarrow{\text{v) } Cu/HBr} \text{Product}$

Which of the following is the most basic?

Alcohol is not formed as a product in

The compound that will react most readily with $NaOH$ to form methanol is

Vedclass Test Series

Exam Paper Generator

Online Exam Module